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4.8t^2+9.8t-9=0
a = 4.8; b = 9.8; c = -9;
Δ = b2-4ac
Δ = 9.82-4·4.8·(-9)
Δ = 268.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.8)-\sqrt{268.84}}{2*4.8}=\frac{-9.8-\sqrt{268.84}}{9.6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.8)+\sqrt{268.84}}{2*4.8}=\frac{-9.8+\sqrt{268.84}}{9.6} $
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